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int 1x {6 (logx) ^2+ 7logx + 2 } d x =

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Click here:point_up_2:to get an answer to your question :writing_hand:6 the value of int frac e 5 log x
int 1x {6 (logx) ^2+ 7logx + 2 } d x =
∫ dx / (x [6(logx)^2+7logx+2] ) - o1fxhx99
int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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int 1x {6 (logx) ^2+ 7logx + 2 } d x =
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